JEE MAIN - Physics (2024 - 6th April Morning Shift - No. 17)
A small ball of mass $$m$$ and density $$\rho$$ is dropped in a viscous liquid of density $$\rho_0$$. After sometime, the ball falls with constant velocity. The viscous force on the ball is :
$$m g\left(1-\frac{\rho_0}{\rho}\right)$$
$$m g\left(\frac{\rho_0}{\rho}-1\right)$$
$$m g\left(1-\rho \rho_0\right)$$
$$m g\left(1+\frac{\rho}{\rho_0}\right)$$
توضيح
$$\begin{aligned}
& F_V=\left(m g-F_B\right) \frac{m g}{m g}=\left(\frac{\rho V_g-\rho_0 V_g}{\rho V_g}\right) m g \\
& F_v=m g\left(1-\frac{\rho_0}{\rho}\right)
\end{aligned}$$